7x^2+4x+35=0

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Solution for 7x^2+4x+35=0 equation:


Simplifying
7x2 + 4x + 35 = 0

Reorder the terms:
35 + 4x + 7x2 = 0

Solving
35 + 4x + 7x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
7 the coefficient of the squared term: 

Divide each side by '7'.
5 + 0.5714285714x + x2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 0.5714285714x + -5 + x2 = 0 + -5

Reorder the terms:
5 + -5 + 0.5714285714x + x2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 0.5714285714x + x2 = 0 + -5
0.5714285714x + x2 = 0 + -5

Combine like terms: 0 + -5 = -5
0.5714285714x + x2 = -5

The x term is 0.5714285714x.  Take half its coefficient (0.2857142857).
Square it (0.08163265305) and add it to both sides.

Add '0.08163265305' to each side of the equation.
0.5714285714x + 0.08163265305 + x2 = -5 + 0.08163265305

Reorder the terms:
0.08163265305 + 0.5714285714x + x2 = -5 + 0.08163265305

Combine like terms: -5 + 0.08163265305 = -4.91836734695
0.08163265305 + 0.5714285714x + x2 = -4.91836734695

Factor a perfect square on the left side:
(x + 0.2857142857)(x + 0.2857142857) = -4.91836734695

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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